Prof Su 苏步青, the founding pioneer Math professor of the China’s top universities (Zhejiang 浙江大学 and Fudan 复旦大学), was one of the few mathematicians who had longevity above 100 years old (the other was French Mathematician Hadammard).

http://en.m.wikipedia.org/wiki/Su_Buqing

Two men A and B are 100 km apart, walking towards each other, A at speed 6 km/hour and B at 4 km/hour.

A brings a dog which runs at 10 km/hour between them, starting from A towards B, upon reaching B it runs back to reach A, then back to B again, and so on…

Find total distance the dog has covered when A and B finally meet ?

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They both took 10 hours to reach each other. the dog ran at a speed of 10km/h. 10h x 10km = 100km distance. the dog ran 100km distance? 🙂

Correct.

100/(4+6) = 10 hours (when both A & B meet)

dog travelled = 10 hrs x 10 km/hr = 100 km.